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24t=-16t^2+54t+24
We move all terms to the left:
24t-(-16t^2+54t+24)=0
We get rid of parentheses
16t^2-54t+24t-24=0
We add all the numbers together, and all the variables
16t^2-30t-24=0
a = 16; b = -30; c = -24;
Δ = b2-4ac
Δ = -302-4·16·(-24)
Δ = 2436
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2436}=\sqrt{4*609}=\sqrt{4}*\sqrt{609}=2\sqrt{609}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-2\sqrt{609}}{2*16}=\frac{30-2\sqrt{609}}{32} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+2\sqrt{609}}{2*16}=\frac{30+2\sqrt{609}}{32} $
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